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A comment on Why don't more physicists subscribe to pilot wave theory?. Parent comment

Re:Why don't more physicists subscribe to pilot wave theory? by dnautics on Friday December 16, 2016 @10:08PM (#13198957)
If I'm not mistaken, It's just formalism. Mathematically a continuous wave function is equivalent to a countably infinite vector space.

It can be hard to switch between the two (as a chemist we are taught Schroeder and I have a hard time wrapping my head around Heisenberg)

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Re:Why don't more physicists subscribe to pilot wave theory? by chestervonwinch on Saturday December 17, 2016 @08:58AM (#13200722)
> a continuous wave function is equivalent to a countably infinite vector space

I think you mean that the function is a point in the vector space. More precisely, it is a point in a particular separable Hilbert space, i.e., a complete vector space equipped with an inner product that has countable, dense basis.

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Re:Why don't more physicists subscribe to pilot wave theory? by dnautics on Sunday December 18, 2016 @12:58AM (#13204573)
right, sorry. The space of continuous wave functions are equivalent to a countably infinite vector space.
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