News for hackers. Stuff that matters.
Re:Mastering Time-to-Market with Haskell by catnaroek on Tuesday November 22, 2016 @11:13AM (#13015060)
You've just defined “pure” as “can be given a denotational semantics”. I have news for you: even ALGOL can be given a denotational semantics.

---

@pron

Nowadays I prefer the terms “effect-free” and “effectful”, rather than “pure” and “impure”, since I don't want to suggest that effects are somehow “wrong” or “evil”. By definition, values are effect-free. An effect is anything that invalidates some equational law that holds for values.

For example, integer equality is decidable, and `x == x` evaluates to `true` when `x` is any integer value. However, if we substitute `x` with the expression `foo()`, where:

    int counter = 0; // or any other initial value
    int foo() { return counter++; }
Then `foo() == foo()` doesn't evaluate to `true` anymore. Hence `foo` is an effectful procedure.

Of course, nontermination is an effect too. If we had defined `foo` as:

    int foo() { while(true); return 0; }
Then `foo() == foo()` would similarly fail to evaluate to `true`.
Re:Mastering Time-to-Market with Haskell by pron on Tuesday November 22, 2016 @11:37AM (#13015254)
Yeah, I know my definitions are problematic. Remember that the term "referential transparency" was introduced to computer science by Strachey in his Fundamental Concepts in Programming Languages as a property of procedural, imperative languages. How would you define pure?

---

> An effect is anything that invalidates some equational law that holds for values.

Ah, I can certainly accept that as a definition, except that I'm not sure how different it is from mine, because the equational law you refer to applies to syntactic terms (`foo` in your example) and the language's equality operator (`==` in your example). It's easy to come with an equivalence relation that would hold for `foo`, but not at the syntax level (e.g., equality that takes `foo` to mean `foo`'s definition and the content of the heap, and the value of `foo` would not be its return value but its behavior -- i.e., the behavior of foo for equal heap contents is always the same).

Re:Mastering Time-to-Market with Haskell by catnaroek on Tuesday November 22, 2016 @02:19PM (#13016702)
> except that I'm not sure how different it is from mine, because the equational law you refer to applies to syntactic terms

An effectful language can be given a denotational semantics. At least from what I've seen, when most people say “pure”, they mean “effect-free”.

> It's easy to come with an equivalence relation that would hold for `foo`, but not at the syntax level [emphasis mine]

Yep, indeed, that's the whole point.

Re:Mastering Time-to-Market with Haskell by pron on Tuesday November 22, 2016 @02:43PM (#13016928)
> when most people say “pure”, they mean “effect-free”

But saying "effect free" doesn't mean much unless you define what an effect is, and what constitutes an effect depends on the language. I meant to define the same thing without referring to another vague definition.

Re:Mastering Time-to-Market with Haskell by catnaroek on Tuesday November 22, 2016 @02:46PM (#13016962)
I already defined above what an effect is. My definicion is technically precise and language-independent.
Re:Mastering Time-to-Market with Haskell by pron on Tuesday November 22, 2016 @03:14PM (#13017237)
OK, so you define effect-freedom using the language's equality operator. I agree it's a better definition than mine, but I think assembly language and BASIC would still qualify as effect-free (provided there's no concurrency) even though some people would not consider them pure.
Re:Mastering Time-to-Market with Haskell by catnaroek on Tuesday November 22, 2016 @03:39PM (#13017449)
> OK, so you define effect-freedom using the language's equality operator.

Not the runtime equality testing operator. Rather, the language's static notion of contextual equivalence.

It just happens to be the case that most high-level languages provide a built-in equality testing operator that works on primitive types, returning `true` iff its operands are contextually equivalent values.

> I think assembly language and BASIC would still qualify as effect-free

I don't even know what a good notion of contextual equivalence for any assembly language would be.

As for BASIC, I haven't used the old ones, so I can't comment on them. I've used Visual Basic, which most certainly has effectful procedures.

Re:Mastering Time-to-Market with Haskell by pron on Tuesday November 22, 2016 @03:47PM (#13017508)
> Not the runtime equality testing operator. Rather, the language's static notion of contextual equivalence.

How is that different from denotational semantics?

> The ones that can be effectful or effect-free are specific computations, not whole languages.

Well, we could define an effect-free language as one where all programs are effect-free. But anyway, what is the "static notion of contextual equivalence" in assembly (or BASIC), and how can you write an effectful program in such a language?