Nothing built in, and generally not recommended, but you can do it! If you want to be really flexible and just allow any attribute, you can do this:

    class Foo:
      def __init__(self, *args, **kwargs):
        self.__dict__.update(**kwargs)

And it will automatically assign any keyword arguments you use as attributes to the object. For example `foo = Foo(name='Bob', age=99)`

If you still want to keep a strict list of allowed attributes, you can define them as parameters, and use a shortcut to assign all local variables to attributes.

    class Foo:
      def __init__(self, name, age):
        self.__dict__.update(locals())
        del self.self

So `foo = Foo(name='Bob', age=99)` will still work as will `foo = Foo('Bob', 99)`. But `foo = Foo('Bob', 99, True)` will throw an error, as will `foo = Foo(name='Bob', age=99, likes_cake=True)`. You can add kwargs back to the parameter list if you want to allow assigning any attribute.

This isn't recommended though. So for all practical purposes, Python does require a bit of boilerplate in the constructor.

Edit: Realized a cleaner way to do the second example.