When you're pulling something along a road or a railtrack on level ground, the primary force you need to overcome is rolling friction, which is proportional to µ×N, where µ is in the range of 0.001 (rail) to 0.01 (road) and N is the normal force against the surface. For a 10 kN car (that's about 1000 kilos), this means that you need a force of about 10 N for a railcar. When you go up an incline, the rolling friction decreases according to the cosine of the angle, but now you need to overcome gravity--and this amount goes up by the sine of the angle. A measly 2% grade requires pulling a force of about 210 N, a factor of 21×.
Basically, grade really kills because you actually have to counteract gravity as opposed to friction.
Second... why's gravity gotta be such a dick? :)
A 2.2% grade seems insignificant to the average person, but to a freight train it is no laughing matter. Here's a serious derailment that happened in California: https://en.wikipedia.org/wiki/San_Bernardino_train_disaster#...
At that grade it's not sufficient to use brakes in the individual rail cars, it's also necessary to use dynamic braking by turning electric traction motors into generators, then dissipating energy in giant resistive grids.
The maximum commercially viable (due to weight restriction) grade for freight railroads is 2.2% ...