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A comment on A Quirky Function. Parent comment

Re:A Quirky Function by jwmerrill on Saturday June 25, 2016 @10:18AM (#11976378)
Yes, the results are the same for 0^f(x) where f(x) is any monotonic function with f(0)=0.
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Re:A Quirky Function by S4M on Saturday June 25, 2016 @10:54AM (#11976501)
f has to be monotonic and increasing, and such as f(x) < 0 if x < 0 , and f(x) > 0 if x > 0 (note the strict inequalities, that makes it a condition slightly stronger than monotonic).
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