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A comment on A Quirky Function. Parent comment

Re:A Quirky Function by qf303rjr3 on Saturday June 25, 2016 @09:34AM (#11976262)
No - you have the following identity because 0 = -0

  0^0 = 0^(-0)
and by the definition of negative exponents,

  0^(-0) = 1/(0^0)
So whatever number 0^0 is, it is equal to its own reciprocal.
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Re:A Quirky Function by fisherjeff on Saturday June 25, 2016 @09:40AM (#11976278)
Ah, ok. I didn't have an issue with the first half, I just misunderstood: I thought he was stating that 0^0 == 1/0^0, not deriving it.
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