Re:Craig Wright Is Not Satoshi Nakamoto
by IgorPartola on Monday May 02, 2016 @07:44PM
(#11616738)
No. If Weight is Satoshi, he knows who Satoshi is, so those are not orthogonal. Basically, the first dimension has four discrete states, while the second has two.
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Re:Craig Wright Is Not Satoshi Nakamoto
by tanderson92 on Monday May 02, 2016 @07:55PM
(#11616794)
Thank you for posting this method of analysis (as well as the poster who pointed to ACH). I think the analytically-minded typically think along these lines, but it is very helpful to me to have a system to formalize around.