> Also IMHO a<b>c should not exist as a comparison. Does this mean a<b AND b>c? Then spell it out, it's a rare case and it doesn't contribute to readability (as opposed to a<b<c for example)
Both are probably broken anyway. The first one will compute as (a < b) > c, and the second one as (a < b) < c. Unless you're using Python which has chained comparison, which has its own pitfalls e.g. `a < b == c > d` may not do what you want (it's equivalent to `a < b and b == c and c > d`, not `(a < b) == (c > d)`)
Also IMHO a<b>c should not exist as a comparison. Does this mean a<b AND b>c? Then spell it out, it's a rare case and it doesn't contribute to readability (as opposed to a<b<c for example)