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A comment on What 50,000 watts of RF energy sounds like through a jumper cable. Parent comment
The numbers you quote (1W [not dBm!] is 7.1V) make me believe that you assume an impedance of 50Ω.
In [1]: math.sqrt(1*50) # P[in W] * R[in Ohm] Out[1]: 7.0710678118654755 # U[in V]
In [2]: math.sqrt(50e3*50) # P[in W] * R[in Ohm] Out[2]: 1581.1388300841897 # U[in V]
Note, though, that with large installations it is likely that there are a few individually tuned feeds. And the cable might not be a 50 Ohm cable, but maybe a chicken ladder (two strands separated by fixed spacers), large-area waveguide, ...
The numbers you quote (1W [not dBm!] is 7.1V) make me believe that you assume an impedance of 50Ω.
So, in an hypothetical cable of 50Ω impedance, 50kW of RF power is... about 1.6kV(RMS).Note, though, that with large installations it is likely that there are a few individually tuned feeds. And the cable might not be a 50 Ohm cable, but maybe a chicken ladder (two strands separated by fixed spacers), large-area waveguide, ...