I don't have any source with me right now, but I've heard that they only whitelist advertisers that pay them (I recall some people comparing this to blackmail).
https://adblockplus.org/about#monetization
TL;DR is that if by participating in the "Acceptable Ads" initiative the organization gains 10 million more ad impressions per month, then they have to pay. If they are "smaller" than that, it's free to them.
Everybody has to keep their ads acceptable, however; you can't bribe your way out of it.
Riiiiight.
On the other hand; it's blackmail. It also falls apart if there are too many competing services or people generally catch on and switch to another ad-blocker. Then companies either pay N-vetting services or their investment is completely wasted. The end result is an (arguably) overly-strict vetting service because people will switch if they don't block enough ads.
As a consumer; I just wanted an ad-blocker sooo....
But the fundamental idea of forcing ad networks to pay for vetting of their ads before they are shown seems very pro-consumer.
Man, this would make me cancel my ticket. I try to avoid being in the same state as Larry Ellison. The evil just oozes.
Don't anthropomorphize the lawnmower. Lawnmower's can't speak. Lawnmowers just mow the lawn.
I wonder if it really is a threat. Serving anything related to ads from same domain as content will make it much harder to create reliable blocking rules[1]. If ad blocking requires heuristics like the ones in Readability extension it won't be as popular.
[1] as a bonus it instantly kills simplistic host file method
For example, ABP blocks our same-domain, self-hosted trackers with the default settings even though our domain is not listed there.
I would guess you are correct. What's ironic is that adblock plus understands their value proposition and whitelists advertisers if they are not too shitty. I run Adblock plus for this very reason (as opposed to a less forgiving blocker).
Also, they just landed Larry Ellison of Oracle as a featured speaker.
http://www.iab.com/