Your answer is merely a simple online search away.

What's weird is five hours after asking that question, no one has provided a reasonable explanation of why C requires arrays to become pointers on function boundaries.

My "online search" found Walter Bright, who knows a thing or two about C compilers, wondering the same thing:

https://news.ycombinator.com/item?id=7572011

Improve your searching capabilities.

https://programmers.stackexchange.com/questions/245602/why-c...

( https://stackoverflow.com/questions/7454990/why-cant-we-pass... )

And partially this thread.

As for Walter; Stop using C like you want it to be used, and instead how it is meant to be used. The article takes a strawman position. Anyone who takes their time and learns C, knows that arrays decay.

So it comes down to historical compatibility with B? Wow.